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Half-Life Calculator

Solve N₀, N_t, t, or t½ for exponential decay — plus convert t½, mean lifetime τ, and decay constant λ.

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How it works

Uses N_t = N₀·(1/2)^(t/t½) = N₀·e^(−λt). Constants: t½ = ln(2)·τ = ln(2)/λ.

N_t = N₀ · (1/2)^(t / t½)

When to use

Use this tool when you need to: decay: leave one blank. Example C-14: N₀=100, N_t=25, t½=5730 → t≈11460. Constants: enter only t½, τ, or λ.

How to use this tool

  1. Enter your values in the fields above.
  2. Review the formula and any mode options for your problem.
  3. Read the result and the step-by-step solution.

Decay: leave one blank. Example C-14: N₀=100, N_t=25, t½=5730 → t≈11460. Constants: enter only t½, τ, or λ.

Frequently asked questions

What is the Half-Life Calculator?
Uses N_t = N₀·(1/2)^(t/t½) = N₀·e^(−λt). Constants: t½ = ln(2)·τ = ln(2)/λ.
How do I use the Half-Life Calculator?
Enter the required values, then calculate. The Half-Life Calculator shows results, formulas, and step-by-step work when available. No account is required.
What formula does the Half-Life Calculator use?
N_t = N₀ · (1/2)^(t / t½)

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Half-life calculator

Generate any one of N₀, N_t, t, or t½ from the other three in the exponential decay formula — or convert among half-life, mean lifetime τ, and decay constant λ.

Provide any three values to calculate the fourth. N_t must be ≤ N₀ for pure decay.

Try an example

How it works

What is half-life?

Half-life is the amount of time it takes a given quantity to decrease to half of its initial value. The term is most commonly used for atoms undergoing radioactive decay, but also describes many other exponential declines. A well-known application is carbon-14 dating. The half-life of carbon-14 is about 5,730 years, and it can measure dates up to roughly 50,000 years. After an organism dies, ¹⁴C decays and the remaining fraction reveals elapsed time.

Definition and formulas

Three equivalent formulas describe exponential decay: N_t = N₀ · (1/2)^(t / t½) N_t = N₀ · e^(−t / τ) N_t = N₀ · e^(−λ t) where N₀ is the initial quantity, N_t the remaining quantity after time t, t½ the half-life, τ the mean lifetime, and λ the decay constant.

Solving for time (carbon-14 example)

If a fossil sample contains 25% of the carbon-14 of a living sample, and t½ ≈ 5,730 y: t = t½ · ln(N_t/N₀) / ln(1/2) t = 5730 · ln(0.25) / ln(0.5) = 11,460 years That age equals exactly two half-lives, since (1/2)² = 1/4.

Half-life, mean lifetime, and decay constant

These three quantities are interchangeable: t½ = ln(2) · τ = ln(2) / λ τ = t½ / ln(2) = 1 / λ λ = ln(2) / t½ = 1 / τ Enter any one in the constants mode to obtain the other two.

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