Learning goals

  • State Ohm’s law and rearrange it for V, I, or R
  • Convert among milli-, base, and kilo- electrical units
  • Choose consistent units before substituting into formulas

Three linked quantities

Voltage (V, volts) is electric potential difference — the “push” that can drive charge. Current (I, amperes) is the flow of charge. Resistance (R, ohms) measures how strongly a component opposes that flow.

For many DC and simple AC circuit estimates, Ohm’s law links them: V = I × R. If you know any two, you can find the third.

Engineering uses metric prefixes constantly: mV, mA, kΩ, MΩ. Convert to base units (V, A, Ω) before multiplying unless every factor shares a consistent scaled system.

Ohm’s law

V = I × R · I = V ÷ R · R = V ÷ I

Use volts, amperes, and ohms together. Example: 12 V across 6 Ω draws I = 12 ÷ 6 = 2 A.

Common prefix factors

1 mA = 0.001 A · 1 kΩ = 1000 Ω · 1 mV = 0.001 V

Move the decimal three places per milli/kilo step. Mega (M) is 10^6; micro (µ) is 10^−6.

Example 1 — Find current

Given

A 9 V battery feeds a 1.8 kΩ resistor. What is the current?

Steps

  1. Convert resistance: 1.8 kΩ = 1800 Ω.
  2. I = V ÷ R = 9 ÷ 1800 = 0.005 A.
  3. Express in milliamps: 0.005 A = 5 mA.

Answer

5 mA.

Example 2 — Milliamps to amps

Given

A USB device draws 500 mA. How many amperes is that?

Steps

  1. 1 mA = 0.001 A, so divide milliamps by 1000.
  2. 500 ÷ 1000 = 0.5.

Answer

0.5 A.

Tip: Power estimates often need amps in base units: P = V × I.

Example 3 — Find resistance

Given

A sensor drops 3.3 V while passing 10 mA. What is its resistance?

Steps

  1. Convert current: 10 mA = 0.01 A.
  2. R = V ÷ I = 3.3 ÷ 0.01 = 330 Ω.

Answer

330 Ω.

Mixing mA with ohms without converting

Common mistake

Computing R = 5 V ÷ 10 mA as 0.5 Ω by treating “10” as amps.

Better approach

10 mA = 0.01 A, so R = 5 ÷ 0.01 = 500 Ω. Or use V ÷ mA carefully: 5 ÷ 10 = 0.5 kΩ = 500 Ω.

Confusing kΩ and Ω on a schematic

Common mistake

Reading “4.7” next to a resistor marked k as 4.7 Ω.

Better approach

4.7 k means 4700 Ω. Prefixes change results by factors of a thousand.

Check your understanding

  1. 1.Convert 2200 Ω to kΩ.

    Answer: 2.2 kΩ.

  2. 2.I = 12 V ÷ 4 Ω. What is I?

    Answer: 3 A.

  3. 3.Convert 250 mV to volts.

    Answer: 0.25 V.

Key takeaways

  • Ohm’s law: V = I × R with volts, amps, and ohms.
  • Convert milli/kilo prefixes before substituting blindly.
  • Power and Ohm’s law need consistent base units.
  • Schematic prefixes (k, M, m) are easy to miss — read them twice.